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A has 2500 rings while B has 225 fewer rings than A. C has 1/5th of a total number of rings of A and B. Who has the least percentage of rings with respect to the total number of rings among all three and approximately how much?

A has 2500 rings while B has 225 fewer rings than A. C has 1/5th of a total number of rings of A and B. Who has the least percentage of rings with respect to the total number of rings among all three and approximately how much? Correct Answer C, 17%

Given,

Number of rings A has = 2500

Number of rings B has = 2500 – 225 = 2275

Total number of rings A and B have = 2500 + 2275 = 4775

Given,

Number of rings C has = 4775 × 1/5 = 955

Total number of rings all three has = 2500 + 2275 + 955 = 5730

Then,

A has percentage of rings = (2500/5730) × 100 = 43.63%

B has percentage of rings = (2275/5730) × 100 = 39.70%

C has percentage of rings = (955/5730) × 100 = 16.66%

∴ From above, C has less percentage number of rings.

Alternate approach:

Since C has the least number of rings, it's quite obvious it will have the least % of rings. Simply find its %.

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