The soil was tested in a National research center and its liquid limit was found to be 15% and the plasticity index was found to be 3%. According to Cassagrande's plasticity chart, which soil type is this?

The soil was tested in a National research center and its liquid limit was found to be 15% and the plasticity index was found to be 3%. According to Cassagrande's plasticity chart, which soil type is this? Correct Answer <span style="">ML</span>

Explanation:

Fine grained soil are classified on the basis of plastic chart. Clay is found to exist above A-line whereas silt & organic soil found to exist below A-line.

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Soil type:

Liquid limit = WL = 15 %, Plasticity index = IP = 3 

IP according to the plasticity chart = 0.73(15 - 20) = - 3.65

And we know IP cannot be negative, and when it comes out negative, we report it as 0

So, according to plasticity chart, IP = 0

Firstly,

The actual plasticity limit is 3, so the soil will lie in the region above A-Line

Secondly, 

By plotting the plasticity index (3) and liquid limit (15 %), in the graph, we get the region of the given soil in the graph above

So, the soil is in the region marked as ML in the graph

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