X sold a car to Y at cost price + 30% of cost price. Y further sold the same car to Z for Rs. 550000 earning a profit of 10% on cost price. Z used car for two years charging the depreciation at the rate of 10% per annum with original cost method. After two years he sold the car at a price which is less than 5% of the original value of the car (Cost price of car at which it is purchased by X). Calculate the profit earned or loss suffered by Z.

X sold a car to Y at cost price + 30% of cost price. Y further sold the same car to Z for Rs. 550000 earning a profit of 10% on cost price. Z used car for two years charging the depreciation at the rate of 10% per annum with original cost method. After two years he sold the car at a price which is less than 5% of the original value of the car (Cost price of car at which it is purchased by X). Calculate the profit earned or loss suffered by Z. Correct Answer Rs. 74615.75 loss

Firstly, we need to calculate the original value of the car to find the profit earned or loss suffered by Z

Let the cost at which Y purchased the car be a

⇒ Profit earned by him = 10a/100 = a/10

⇒ Selling price = a + (a/10) = 11a/10

ATQ,

⇒ 11a/10 = 550000

⇒ a = 500000

So, Cost price at which car is purchased by Y = Rs. 500000

Cost price of Y is the selling price of X

Let the original cost at which X has purchased the car be b

⇒ Profit earned by him = 30a/100 = 3a/10

⇒ Selling price = b + (3b/10) = 13b/10

⇒ 500000 = 13b/100

⇒ b = 384615

⇒ The original cost at which X has purchased the car = Rs. 384615

Now, we have to calculate the value of car with Z at the time of selling

⇒ Price at which Z purchased the car = Rs. 550000

⇒ Depreciation for two years at the rate of 10% p.a. = 2 × (10% of 550000) = 2 × 55000 = Rs. 110000

⇒ Value of the car after two years = 550000 – 110000 = Rs. 440000       ---- (1)

⇒ Price at which car is sold by Z = 384615 – (5% of 384615) = 384615 – 19230.75 = Rs. 365384.25        ---- (2)

From equation (1) and (2)

⇒ Loss suffered by Z on sale = 440000 – 365384.25 = 74615.75

∴ The selling price is less than the value of car. So, loss suffered by Z on sale is Rs. 74615.75

Related Questions

Each of the question below consists of a question and three statements number I, II and III given below it. You have to decide whether the data provided in the statement are sufficient to answer the question. If the bus is travelling from Surat to Ahmadabad and a car is travelling from Ahmadabad to Surat, then what is the distance between Surat and Ahmadabad? I. The speed of a car is 40% less than the speed of bus. Bus started at 9 am and car started at 10 am and they meet at 3 pm of the same day. II. After travelling for 1 hour, because of traffic average speed of bus is decreased by 20% and covers distance between Surat to Ahmadabad in 11 hours. Original speed of car is 20% less than original speed of bus and before crossing bus it covered 200 km if starts 1 hour later than bus. After crossing car, bus covers remaining distance in 5 hours. III. Speed of bus is 10 km/hr more than the speed of car and before crossing car ratio of distances covered bus and car in same time was 5 : 4. Time taken by car to cover the distance between Ahmadabad and Surat is 2 hours 15 minutes more than time taken by bus to cover the same distance.