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A man covers a certain distance(in m) in 15 minutes and then covers a distance which is equal to three times of the previous distance in 45 minutes and again travels a distance twice the previous distance in 1 hour 30 minutes. If the average speed of the man is 50 m/min, then find the half of the total distance covered by man.

A man covers a certain distance(in m) in 15 minutes and then covers a distance which is equal to three times of the previous distance in 45 minutes and again travels a distance twice the previous distance in 1 hour 30 minutes. If the average speed of the man is 50 m/min, then find the half of the total distance covered by man. Correct Answer 3750 m

Formula used:

Speed = distance/time

Average speed = total distance /total time

Calculation:

Let the distance covered by the man in 1st period of time be x m

So, the distance covered by the man in 2nd period of time is 3x m

So, the distance covered by the man in 3rd period of time is 6x m

So, total distance = x + 3x + 6x = 10x

Now,

Average speed = (total distance covered)/(total time taken)

50 = 10x/(15 + 45 + 90)

⇒ 10x = 50 × 150

⇒ 10x = 7500 m

So, half of the total distance = 7500/2 = 3750 m

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