Consider a two-sided discrete-time signal (neither left sided, nor right sided). The region of convergence (ROC) of the z-transform of the sequence is: 1) All region of z-plane outside a unit circle (in z-plane) 2) All region of z-plane inside a unit circle (in z-plane) 3) Ring in z-plane Which of the above is/are correct?

Consider a two-sided discrete-time signal (neither left sided, nor right sided). The region of convergence (ROC) of the z-transform of the sequence is: 1) All region of z-plane outside a unit circle (in z-plane) 2) All region of z-plane inside a unit circle (in z-plane) 3) Ring in z-plane Which of the above is/are correct? Correct Answer 3 only

Concept:

Properties of ROC of Z-Transform:

i) The ROC of Z-transform X(z) is in the form of a circle centered about the origin.

ii) The ROC of z-transform X(z) never contains any poles.

iii) X(n) is a right-sided signal and if the ROC contains r = r0 , then all the circles for which r0 < r < ∞ will also be present in the ROC

iv) If X(n) is a left-sided signal & if the circle (r = r0) is in the ROC then all values of r for which 0 < r < r0 will also be present in ROC.

v) For a right-sided signal, the ROC is always outer to the outermost pole excluding infinity

vi) For a left-sided signal, the ROC is always left to the innermost non-zero pole

vii) For a two-sided signal, the ROC is between the two circles (poles) but does not contain any pole

viii) For finite duration absolutely summable signal, the ROC is entire Z-plane except possibly for Z = 0 and/or Z = ∞

Application:

From the above exclamation of point (vi), we can conclude that for a two-sided signal, the ROC of Z-transform service is a ring in the Z-plane.

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