A person X wants to distribute some pens among six children A, B, C, D, E, and F. Suppose A gets twice the number of pens received by B, three times that of C, four times that of D, five times that of E and six times that of F. What is the minimum number of pens X should buy so that the number of pens each one gets is an even number?

A person X wants to distribute some pens among six children A, B, C, D, E, and F. Suppose A gets twice the number of pens received by B, three times that of C, four times that of D, five times that of E and six times that of F. What is the minimum number of pens X should buy so that the number of pens each one gets is an even number? Correct Answer 294

Calculation:

Let A gets x pens.

B = x/2

C = x/3

D = x/4

E = x/5

F = x/6

LCM of 2, 3, 4, 5, 6 = 60

The possible value of x = 60, 120, 180, .........

According to question

The number of pens each one gets is an even number

∴ x =120 ( as minimum possible value)

A =120

B = 60

C = 40

D = 30

E = 24

F = 20

Total number of pens = 294

Hence, option 3 is correct.

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