A person X wants to distribute some pens among six children A, B, C, D, E, and F. Suppose A gets twice the number of pens received by B, three times that of C, four times that of D, five times that of E and six times that of F. What is the minimum number of pens X should buy so that the number of pens each one gets is an even number?
A person X wants to distribute some pens among six children A, B, C, D, E, and F. Suppose A gets twice the number of pens received by B, three times that of C, four times that of D, five times that of E and six times that of F. What is the minimum number of pens X should buy so that the number of pens each one gets is an even number? Correct Answer 294
Calculation:
Let A gets x pens.
B = x/2
C = x/3
D = x/4
E = x/5
F = x/6
LCM of 2, 3, 4, 5, 6 = 60
The possible value of x = 60, 120, 180, .........
According to question
The number of pens each one gets is an even number
∴ x =120 ( as minimum possible value)
A =120
B = 60
C = 40
D = 30
E = 24
F = 20
Total number of pens = 294
Hence, option 3 is correct.
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Feb 20, 2025