A conical vessel of radius 7 cm and height 30 cm is completely filled with a liquid. From it, the liquid is poured into several conical vessels of radius 5 cm and height 21 cm, thereby filling them completely. What part of the last conical vessel will remain empty? Use π = 22/7.

A conical vessel of radius 7 cm and height 30 cm is completely filled with a liquid. From it, the liquid is poured into several conical vessels of radius 5 cm and height 21 cm, thereby filling them completely. What part of the last conical vessel will remain empty? Use π = 22/7. Correct Answer 1/5

As we know, a cone with radius ‘r’ and height ‘h’, has a volume = 1/3 πr2h

Total volume of liquid = volume of first conical vessel = (1/3) × (22/7) × (7)2 × 30 = 1540 cm3

Volume of liquid poured in one vessel = volume of second conical vessel

= (1/3) × (22/7) × (5)2 × 21 = 550 cm3

Total number of vessels filled = 1540/550 = 2.8

Hence, the third vessel is only filled = 0.8 = 80%

∴ The last vessel remained empty by = 100 – 80 = 20% = 1/5

Related Questions

Each question below is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer. What is the ratio of coconut oil and milk in the final beaker? If contents from four vessels poured in it. I. Vessel B has 10 ml more capacity than vessel A and the ratio of coconut oil and milk in vessel B is 2 ∶ 7. Vessel C has coconut oil and milk in the ratio 2 ∶ 3 and contains 38 ml more capacity than Vessel D II. Vessel A has milk and coconut oil in the ratio 3 ∶ 5. Vessel C has 12 ml more coconut oil than vessel D.