If sec2 θ - sec θ = 1, then what is the value of tan12 θ - 3 tan10 θ + 3 tan8 θ - tan6 θ ?
If sec2 θ - sec θ = 1, then what is the value of tan12 θ - 3 tan10 θ + 3 tan8 θ - tan6 θ ? Correct Answer 1
According to equation,
sec2 θ - sec θ = 1
1 + tan² θ = 1 + sec θ
tan² θ = sec θ ---- eq (1)
now Given
tan12 θ - 3 tan10 θ + 3 tan8 θ - tan6 θ = (tan⁴ θ - tan² θ)³
now put values from equation 1
(sec2 θ - sec θ)3 = 13 = 1
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Feb 20, 2025