If sec2 θ - sec θ = 1, then what is the value of tan12 θ - 3 tan10 θ + 3 tan8 θ - tan6 θ ?

If sec2 θ - sec θ = 1, then what is the value of tan12 θ - 3 tan10 θ + 3 tan8 θ - tan6 θ ? Correct Answer 1

According to equation,

sec2 θ - sec θ = 1 

1 + tan² θ = 1 + sec θ  

tan² θ = sec θ    ---- eq (1)

now Given

tan12 θ - 3 tan10 θ + 3 tan8 θ - tan6 θ = (tan⁴ θ - tan² θ)³

now put values from equation 1

(sec2 θ - sec θ)3 = 13 = 1

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What is the value of [sec θ/(sec θ - 1)] + [sec θ/(sec θ + 1)]?