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In an alloy, lead and tin are in the ratio of 2 : 3. In the second alloy, the ratio of same elements is 3 : 4. If equal quantities of these two alloy are mixed to form a new alloy, then what will be the ratio of these two elements in the new alloy?

In an alloy, lead and tin are in the ratio of 2 : 3. In the second alloy, the ratio of same elements is 3 : 4. If equal quantities of these two alloy are mixed to form a new alloy, then what will be the ratio of these two elements in the new alloy? Correct Answer 29 : 41

Let ‘x’ quantity of each of two alloy be mixed

Quantity of lead in the new alloy = (2/5)x + (3/7)x = 29x/35

Quantity of tin in the new alloy = (3/5)x + (4/7)x = 41x/35

∴ Required ratio = (29x/35) ∶ (41x/35) = 29 ∶ 41

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