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In an alloy, aluminium and tin are in the ratio of 4 ∶ 5. In the second alloy, the ratio of same elements is 4 ∶ 7. If equal quantities of these two alloys be mixed to form a new alloy, then what will be the ratio of both of these elements in the new alloy?

In an alloy, aluminium and tin are in the ratio of 4 ∶ 5. In the second alloy, the ratio of same elements is 4 ∶ 7. If equal quantities of these two alloys be mixed to form a new alloy, then what will be the ratio of both of these elements in the new alloy? Correct Answer 40 ∶ 59

Let the quantity of both the alloys are p kg

Total quantity of aluminium = (4p/9 + 4p/11) = 80p/99

Total quantity of tin = (5p/9 + 7p/11) = 118p/99

∴ Required ratio = 80p/99 ∶ 118p/99 = 80 ∶ 118 = 40 ∶ 59

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