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The total pressure of water vapour, nitrogen and hydrogen is 864 mmHg. The partial pressure of nitrogen is 410 mmHg and that of hydrogen is 220 mmHg. What is the partial pressure of water vapour?

The total pressure of water vapour, nitrogen and hydrogen is 864 mmHg. The partial pressure of nitrogen is 410 mmHg and that of hydrogen is 220 mmHg. What is the partial pressure of water vapour? Correct Answer 234 mmHg

Given,

Ptotal = 864 mmHg

PN= 410 mmHg

PH= 220 mmHg

To find PW

According to Dalton's law of partial pressures,

Ptotal = PN + PH + PW

So, PW = 864 - 410 - 220

            = 234 mmHg

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