If sinθ + tanθ = 3√3/2, then what is the value of 5cosθ - 2sin2θ + 4tan2θ?
If sinθ + tanθ = 3√3/2, then what is the value of 5cosθ - 2sin2θ + 4tan2θ? Correct Answer 13
sinθ + tanθ = 3√3/2
sinθ + (sinθ/cosθ) = (√3 + 2√3)/2
sinθ + (sinθ/cosθ) = (√3/2) + √3
sinθ + (sinθ/cosθ) = (√3/2) +
After comparing:
sinθ = √3/2
cosθ = 1/2
tanθ = √3
Now,
= 5cosθ - 2sin2θ + 4tan2θ
= 5 × (1/2) - 2 × (√3/2)2 + 4 × (√3)2
= (5/2) - (3/2) + 12
= 13
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Feb 20, 2025