Given that, a =3+2 =1a=13+2=3-2(3+2)(3+2)=3-2(3)2-(2)2=3-23-2=3-21 ∴1a=3-2 ∴a+1a=3+2+3-2=23...........(i) now, a3+1a3=(a+1a)3-3a×1a(a+1a) =(23)3-3×23 =23×(3)3-63 =8×33-63 =243-63 =183 (proved)
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