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Radius of semi circular sheet, r = 28214m 

Circumference of the sheet = πr=227×14=44cm

Here, circumference of semi circle will be equal to the circumference of the base of cone.

Now, let the radius of the base of cone = R

According to question = = 2πR=44 =R=442π=4422×27=44×722×2=7cm 

Here, radius of semi circle equals to the height of cone.

That mean's  l = r = 14 cm 

Now, we know 2=h2+R2h2=l2-R2h2=142-72=196-49=147h=49×3=72×3=73h=73 

So, the depth is 73  cm and 

The capacity will be = 13πr2h=13×227×72×73=622.37cm3 (ans)

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