In a sequence of 12 consecutive odd numbers, the sum of the first 5 numbers is 425. What is the sum of the last 5 numbers in the sequence?
Md Ariful Islam
বিএসসি(সিএসই)
,
এমবিএ(মার্কেটিং)
4 views
1 Answers
Dr. Md Rushad Rahman
এমবিবিএস(আরপিএমসি)
,
পিজিটি(মেডিসিন)
The sum of the last 5 numbers in the sequence make up 495. If we state that "n" represents any odd number and start our sequence: n + (n+2) + (n+4) + (n+6) + (n+8) = 425, where n = 81. If we continued this sequence, the last 5 consecutive odd numbers can be represented by: (n+14) + (n+16) + (n+18) + (n+20) + (n+22). By substituting n = 81 into this sequence, we get 495. Another way is to write out 12 consecutive odd numbers starting with 81 and then adding the last 5 numbers.
4 views
Answered