It is known that a box of 800 electric bulbs contains 36 defective bulbs .
One bulb is taken at random of the box. What is the probability that the bulb chosen is nondefective ?
Given: I = 6 A, t = 4 hrs = 4 × 60 × 60 s
To find: Number of electrons (N)
Formula: I = \(\frac{q}{t}=\frac{Ne}{t}\)
Calculation: As we know, e = 1.6 ×...
Let X be the random variable defined as the number of red balls.
Then X = 0, 1
P(X = 0) = \(\frac{3}{4}\times\frac{2}{3}=\frac{6}{12}=\frac{1}{2}\)
P(X = 1) = \(\frac{1}{4}\times\frac{3}{3}+\frac{3}{4}\times\frac{1}{3}=\frac{6}{12}=\frac{1}{2}\)
Probability Distribution Table:
X
0
1
P(X)
\(\frac{1}{2}\)
\(\frac{1}{2}\)