An urn contains 9 red, 7 white and 4 black balls. A ball is drawn at random. Find the probability that the ball drawn is (i) red (ii) white (iii) red

Correct Answer - B `(b)` Let `A` be the event of drawing a black ball. `A_(1)`, the event of choosing the first box. `A_(2)`, the event of choosing the second box....

Correct Answer - `(43)/(50)`

Correct Answer - `13/204`

Correct Answer - `5/9`

Correct Answer - ` (i) 1/10 (ii) (a) 9/10 (b) 1/5`

Correct Answer - `4/13`

Let X be the random variable defined as the number of red balls. Then X = 0, 1 P(X = 0) = \(\frac{3}{4}\times\frac{2}{3}=\frac{6}{12}=\frac{1}{2}\) P(X = 1) = \(\frac{1}{4}\times\frac{3}{3}+\frac{3}{4}\times\frac{1}{3}=\frac{6}{12}=\frac{1}{2}\) Probability Distribution Table: X 0 1 P(X) \(\frac{1}{2}\) \(\frac{1}{2}\)

The required probability = P((The first is a red jack card and The second is a jack card) or (The first is a red non-jack card and The second is...

Correct option is (B) 3 2/3 Let sum of scored runs on first 5 balls in the last over is x. After hitting 6 on last ball of the over, the mean...