If the momentum of a body is doubled, its KE. increases by (A) 50% (B) 300% (C) 100% (L) 400%
If the momentum of a body is doubled, its KE. increases by
(A) 50%
(B) 300%
(C) 100%
(L) 400%
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2 Answers
Correct option is: (B) 300%
Kinetic energy , K = \(\frac{P^2}{2m}\)
When momentum p is doubled , the kinetic energy becomes
\(K^1 = \frac{(2p)}{2m}\)
\(K^1 = 4 (\frac{p^2}{2m})\)
\(K^1 = 4K\)
increases in kinetic energy = \(\frac{K^1 - K}{K}\)
\(= \frac{4K - K}{K} \times 100\)
\(\left(\frac{3K}{K}\right) \times 100\)
300%
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