A body of mass m strikes a wall with velocity v and rebounds with the same speed. Its change in momentum is
A body of mass m strikes a wall with velocity v and rebounds with the same speed. Its change in momentum is
(A) 2 mv
(B) mv/2
(C) – mv
(D) Zero
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Correct Option is: (A) 2 mv
Initial velocity of body before collision u = v
then initial momentum Pi = - MV
final velocioty of the body \(P_f = MV\)
Change in momentum
\(\Delta P = P_f - P_i\)
\(MV - (-MV)\)
2 MV
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