If m is the mass of a body and E its K.E..then its linear momentum is

(A) \(m\sqrt{E}\)

(B) \(2\sqrt{m}E\)

(C) \(\sqrt{m}E\)

(D) \(\sqrt{2mE}\)

7 views

2 Answers

Correct option is: (D) \(\sqrt{2mE}\)

\(E = \frac{1}{2} mv^2\)

\(v = \sqrt \frac{2E}{m}\)

\(P = mv\)

\(P = m \sqrt \frac{2E}{m}\)

\(P = \sqrt{2mE}\)

7 views

Correct option is: (D) \(\sqrt{2mE}\)

7 views

Related Questions