A jet airplane travelling at the speed of 500 kmh^-1 ejects the burnt gases at the speed of 1400 kmh^-1 relative to the jet airplane.
A jet airplane travelling at the speed of 500 kmh-1 ejects the burnt gases at the speed of 1400 kmh-1 relative to the jet airplane. The speed of burnt gases relative to stationary observer on the earth is
(A) 2.8 kmh-1
(B) 190 kmh-1
(C) 700 kmh-1
(D) 900 kmh-1
4 views
2 Answers
Correc Option is (D) 900 \(kmh^{-1}\)
\(v_p = -500\) km/h
\(V_{gp} = 1400\) km/h
The speed of burnt gas with respect to the jet airplane is
\(\overrightarrow v_{gp} = \overrightarrow v_g - \overrightarrow v_p\)
\(1400 = v_g + 500\)
\(v_g = 1400 - 500\)
\(v_g = 900\) km/h
4 views
Answered