The velocity-time relation of a particle starting from rest is given by v = kt where k = 2 m/s^2. The distance travelled in 3 sec is
The velocity-time relation of a particle starting from rest is given by v = kt where k = 2 m/s2. The distance travelled in 3 sec is
(A) 9 m
(B) 16 m
(C) 27 m
(D) 36 m
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2 Answers
Correct Option is (A) 9 m
Given,
V = kt
\(\because v = \frac{dx}{dt}\)
\( \frac{dx}{dt} = kt\)
\(\int\limits_0^x dx = \int\limits_ 0^3 kt \ dt\)
\(x = k \left[\frac{t}{2}\right]_0^3\)
\(x = k \left[\frac{9}{2}\right]\)
\(x = 2 \times \frac{9}{2}\).
x = 9 m
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