A particle is projected vertically upwards from the earth. It crosses the same point at t=2 sec and t=8 sec. Find out `[g=10 ms^(-2)]`
(i) the time for which particle remains in air
(ii) intial velocity of particle
(iii) maximum height attained by the particle
(iv) height of the particle at t=2 sec and t=8 sec from earth


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Correct Answer - (i) 10 sec
(ii) 50 m//s
(iii) 125 m
(iv) 80 m

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