A book with many printing errors contains four different formulae for the displacement y of a particle undergoing a certain periodic function:

(i) y = a sin \(\frac{2\pi t}{T}\)

(ii) y = a sin v t

(iii) y = \(\frac{a}{T}\) sin \(\frac{t}{a}\)

(iv) y = \(\frac{a}{\sqrt{2}}[sin \,\frac{2\pi t}{T}+cos\,\frac{2\pi t}{T}]\)

Here, a is maximum displacement of particle, y is speed of particle, T is time period of motion.

Rule out the wrong formulae on dimensional grounds.

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1 Answers

The argument of trigonometrical function, i.e., angle is dimensionless. 

Now,

(i) The argument, \([\frac{2\pi t}{T}]=\frac{[T]}{[T]}\) = 1 = [L0M0T0]

which is a dimensionless quantity.

Hence, formula (i) is correct.

(ii) The argument,

[vt] = [LT-1] [T] = [L] = [L1M0T0]

which is not a dimensionless quantity.

Hence, formula (ii) is incorrect.

(iii) The argument,

\([\frac{t}{a}]=\frac{[T]}{[L]}\) = [L-1M0T1]

which is not a dimensionless quantity.

Hence, formula (iii) is incorrect.

(iv) The argument,

\([\frac{2\pi t}{T}]=\frac{[T]}{[T]}\) = 1 = [L0M0T0]

which is a dimensionless quantity.

Hence, formula (iv) is correct.

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