A point moves such that its displacement as a function of time is given by `x^3 = t^3 + 1`. Its acceleration as a function of time t will be

Question

A point moves such that its displacement as a function of time is given by `x^3 = t^3 + 1`. Its acceleration as a function of time t will be

A point moves such that its displacement as a function of time is given by `x^3 = t^3 + 1`. Its acceleration as a function of time t will be
A. `(2)/(x^(5))`
B. `(2t)/(x^(5))`
C. `(2t)/(x^(4))`
D. `(2t^(2))/(x^(5))`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`x^(2)=t^(3)+1 rArr 3x^(2)(dx)/(dt)=3t^(2)`
`x^(2)v=t^(2) rArr 2x(dx)/(dt)v+x^(2)a=2t`
`2x(t^(4))/(x^(4))+x^(2)a=2trArr x^(2)a=2t-(2t^(4))/(x^(3))`
`a=(2t[x^(3)-t^(3)])/(x^(5))rArr a-(2t)/(x^(5))`

5 views Answered 2023-02-05 15:29