For a certain thermocouple , `varepsilon=alphatheta+(1)/(2)betatheta^(@),where theta.^(@)C` is the temperature of the hot junction and `0^(@)C` is the

For a certain thermocouple , `varepsilon=alphatheta+(1)/(2)betatheta^(@),where theta.^(@)C` is the temperature of the hot junction and `0^(@)C` is the temperature of the cold junction . If `alpha =10 mu V.^(@)C^(-1)` and `beta=-(1)/(20)muV.^(@)C^(-2)`, find the neutral temperature and temperature of inversion.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - `200^(@)C , 400.^(@)C`

4 views Answered 2023-02-05 15:29

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