The emf in a lead-iron thermocouple , one junction of which is at `t^(@)C` is given by `varepsilon=178t-2.4t^(2)( "in "muV)` where t is the temperatur

Question

The emf in a lead-iron thermocouple , one junction of which is at `t^(@)C` is given by `varepsilon=178t-2.4t^(2)( "in "muV)` where t is the temperatur

The emf in a lead-iron thermocouple , one junction of which is at `t^(@)C` is given by
`varepsilon=178t-2.4t^(2)( "in "muV)`
where t is the temperature in `.^(@)C` .Find the neutral temperature , Peltier coefficient and Thomson coefficient.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - `371.67.^(@)C, 3094.4 T-4.8 T^(2),-4.8T`

5 views Answered 2023-02-05 15:29