The emf `varepsilon` of a Cu-Fe thermocouple varies with the temperature `theta` of the hot junction (cold junction at `0^(@)C` ), as `varepsilon(mu V

Question

The emf `varepsilon` of a Cu-Fe thermocouple varies with the temperature `theta` of the hot junction (cold junction at `0^(@)C` ), as `varepsilon(mu V

The emf `varepsilon` of a Cu-Fe thermocouple varies with the temperature `theta` of the hot junction (cold junction at `0^(@)C` ), as `varepsilon(mu V)=14 theta-0.02 theta^(2)` Determine the neutral temperature.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

At neutral temperature `(dE)/(dtheta)=0 therefore 14-2(0.02theta_(n))=0rArr theta_(n)=(14)/(0.04)=350^(@)C`

7 views Answered 2023-02-05 15:29