1 mole each of A and D is intoduced in 1 litre container. Simultaneously the following two equilibria are established: `A hArrB+C K_(C)=10^(6)M^(2)` `

Question

1 mole each of A and D is intoduced in 1 litre container. Simultaneously the following two equilibria are established: `A hArrB+C K_(C)=10^(6)M^(2)` `

1 mole each of A and D is intoduced in 1 litre container. Simultaneously the following two equilibria are established:
`A hArrB+C K_(C)=10^(6)M^(2)`
`B+DhArrA K_(C)=10^(-6)M^(-1)`
The equilibrium concentration of A will be
A. `10^(-3)M`
B. `10^(-12)M`
C. `10^(-6)M`
D. `10^(-4)M`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`AhArrB+C`….(i)
`K_(C)=10^(6)`
`{:("Assume",l-I,I),("at eqm x",1-x,1-x):}`
`B+DhArr A`….(ii)
`K_(c)=10^(-6)`
at eqm `1-x 10x x`
by i+ii
`DhArrCK_(C)=10^(6)xx10^(-6)=1`
at eqm 1-x 1-x
For (i) `k_(c)=10^(6)=(IxxI)/(x)rArrx=10^(-6)`

4 views Answered 2023-02-05 15:29