The formula of rust can be represented by `Fe_(2)O_(3)`. How many mole of Fe are present in 16 gm of rust.
The formula of rust can be represented by `Fe_(2)O_(3)`. How many mole of Fe are present in 16 gm of rust.
A. 0.1
B. 0.2
C. 0.4
D. 0.3
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16 gm rust `rArr(16)/(160)` moles of rust
0.1mole of rust
moles of `Fe=2xx("molar of rust")`
`=2xx0.1=0.2`
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