The bond distance between H-atom in `H_(2)` and X-atoms in `X_(2)` is 74 pm and 124 pm respectively. Find distance between H and X in HX electronegati

Question

The bond distance between H-atom in `H_(2)` and X-atoms in `X_(2)` is 74 pm and 124 pm respectively. Find distance between H and X in HX electronegati

The bond distance between H-atom in `H_(2)` and X-atoms in `X_(2)` is 74 pm and 124 pm respectively. Find distance between H and X in HX electronegativity (EN) of H is 2.1 and X is 3.1 in pauling scale. Use Stevenson-Schomaker formula.
[Divide your answer by 10]

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`d_(H-X)=r_(H)+r_(X)-0.09|r_(X)+r_(H)|` where `r_(H) & r_(X)`
put in `overset(@)A` unit. `d_(H-X)=37xx10^(-2)+62xx10^(-2)-0.09xx1=0.99`
`0.09=0.90 overset(@)A=90pm`
`=(90)/(10)=9`

4 views Answered 2023-02-05 15:29