The average energy required to break a P-P bond in `P_(4)(s)` into gaseous atoms is `53.2 kcal mol^(-1)`. The bond dissociation energy of `H_(2)(g)` i

Question

The average energy required to break a P-P bond in `P_(4)(s)` into gaseous atoms is `53.2 kcal mol^(-1)`. The bond dissociation energy of `H_(2)(g)` i

The average energy required to break a P-P bond in `P_(4)(s)` into gaseous atoms is `53.2 kcal mol^(-1)`. The bond dissociation energy of `H_(2)(g)` is `104.2kcal mol^(-1) , Delta H_(f)^(0)` of `PH_(3)(g)` from `P_(4)(s)` is `5.5 kcal mol^(-1)`. The P-H bond energy in kcal `mol^(-1)` is [ Neglect presence of Van der Waals force in `P_(4)(s)`]
A. 85.2
B. 57.6
C. 76.9
D. 63.3

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`nCH_(2)=CH_(2)rarr(-CH_(2)-CH_(2)-)_(n) DeltaH= -100 KJ//"mole"`
Double bond of ethylene converted to two single bonds.
`DeltaH= -100=B.E._(C-C)-2B.E._(C-C)`
`rArr -100=600-2xxB.E._(C-C)rArr B.E._(C-C)rArrB.E._(C-C)=350 kJ//"mole"`

6 views Answered 2023-02-05 15:29