If enthalpy of dissociation of `CH_(4)` and `C_(2)H_(6)` are `320` and `360` calories respectively then bond energy of `C-C` bond is:
If enthalpy of dissociation of `CH_(4)` and `C_(2)H_(6)` are `320` and `360` calories respectively then bond energy of `C-C` bond is:
A. `80 cal`
B. `40 cal`
C. `60 cal`
D. `120 cal`
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Correct Answer - D
`CH_(4) rarrC+4H`
`Delta H=320=Delta H_(C-H), Delta H_(C-H)=80`
`C_(2)H_(6)rarr2C+6H`
`Delta H=360 =Delta H_(C-C)+6 Delta H_(C-H)`
`360=Delta H_(C-C)+6xx80`
`Delta H_(C-C)= -120 cal`
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