In `S_(N^(2))` reactions, the correct order of reactivity for the compounds `CH_(3)Cl,CH_(3)CH_(2)Cl,(CH_(3))_(2)CHCl` and `(CH_(3))_(3)C Cl` is:

Question

In `S_(N^(2))` reactions, the correct order of reactivity for the compounds `CH_(3)Cl,CH_(3)CH_(2)Cl,(CH_(3))_(2)CHCl` and `(CH_(3))_(3)C Cl` is:

In `S_(N^(2))` reactions, the correct order of reactivity for the compounds `CH_(3)Cl,CH_(3)CH_(2)Cl,(CH_(3))_(2)CHCl` and `(CH_(3))_(3)C Cl` is:
A. `CH_(3)Cl gt (CH_(3))_(2) CHCl gt CH_(3)CH_(2)Cl gt (CH_(3))_(3) C Cl`
B. `CH_(3)Cl gt CH_(3)CH_(2)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3) C Cl`
C. `CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3)C Cl`
D. `(CH_(3))_(2) CHCl gt CH_(3)CH_(2) Cl gt C H_(3)Cl gt (CH_(3))_(3)C Cl`

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
It is an example of `S_(N^(2))` reaction. The order of reactivity is inversely proportional to the steric hindrance offered by the alkyl groups.

7 views Answered 2023-02-05 15:29