Let ABCD be a parallelogram whose equations for the diagonals AC and BD are x+2y=3 and 2x+y=3, respectively. The length of side AB is equal to
Let ABCD be a parallelogram whose equations for the diagonals AC and BD are x+2y=3 and 2x+y=3, respectively.
The length of side AB is equal to
A. `2sqrt(58)//3`
B. `4sqrt(58)//9`
C. `3sqrt(58)//9`
D. `4sqrt(58)//9`
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Correct Answer - A
`"cos" (pi-theta) = (AP^(2) + PB^(2)-AB^(2))/(2AP xx PB)`
`"or " -(4)/(5) = (4+(100//9)-AB^(2))/(2 xx 2 xx (10//3))`
`"or " AB = (2sqrt(58))/(3)`
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