A particle starts moving from rest under a constant acceleration. It travels a distance x in the first 10 sec and distance y in the next 10 sec, then

Question

A particle starts moving from rest under a constant acceleration. It travels a distance x in the first 10 sec and distance y in the next 10 sec, then

A particle starts moving from rest under a constant acceleration. It travels a distance x in the first 10 sec and distance y in the next 10 sec, then
A. y = x
B. y = 2x
C. y = 3x
D. y = 4x

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

A body P starts from rest with an acceleration `a_(1)`. After 2 seconds, another body Q starts from rest with an acceleration `a_(2)` from the same po

2 Answers 5 Views

A particle starts moving at t = 0 in a circle of radius `R = 2m` with constant angular acceleration of `a - 3 "rad/sec"^(2)`. Initial angular speed of

2 Answers 4 Views

A radioactive element decays by `beta-`emission. A detector racords `n`-beta particles in `2` sec and in next `2` sec it records `0.65n`-beta particle

2 Answers 5 Views

A body has to travel 120km distance. It travels first 30km with uniform speed 30km/hr. Its average speed is 60 km/hr. What should be its speed in next

2 Answers 6 Views

A particle starts from origin at t=0 with velocity `5.0hati m//s` and move in x.y plane under action of a force which produces a constant acceleration

2 Answers 6 Views

A particle revolving in a circular path completes first one third of circumference in 2 sec, while next one third in 1 sec. The average angular veloci

2 Answers 8 Views

A particle starts from rest from the top of an inclined plane and again comes to rest on reaching the bottom most point of the inclined plane. If the

2 Answers 9 Views

A body starts revolving from rest in a circular path of radius 2 m with tangential acceleration a `=2tm//s^(2)`. If its total acceleration at t=2 sec.

2 Answers 5 Views

A particle starts from rest on a straight path, Its acceleration is linearly varying with time, such that velocity of the particle at t=2 sec and t=4

2 Answers 5 Views

A particle starts moving on circular path of radius `(9)/(4)m` with tangential acceleration `3ms^(-2)`. Find angle between acceleration of the particl

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`x = 0t +(1)/(2)a 10^(2)`
`x +y = 0t +(1)/(2)a(10+10)^(2)`
`x = 50a " ".........(1)`
`x+y=200a " "..........(2)`
solving y = 3x is obtained `therefore (C )`
Correct is (C )

4 views Answered 2023-02-05 15:29