A particle revolving in a circular path completes first one third of circumference in 2 sec, while next one third in 1 sec. The average angular veloci

Question

A particle revolving in a circular path completes first one third of circumference in 2 sec, while next one third in 1 sec. The average angular veloci

A particle revolving in a circular path completes first one third of circumference in 2 sec, while next one third in 1 sec. The average angular velocity of particle will be – ("in "rad//sec)

Monjur Alahi

8 views

2025-01-04 04:42

1 Answers

Related Questions

If a particle rotates along a circle of radius 3 m with an angular acceleration of `(pi)/(2) "rad"//s^(2)` starting from rest, then its average veloci

2 Answers 5 Views

A particle starts moving at t = 0 in a circle of radius `R = 2m` with constant angular acceleration of `a - 3 "rad/sec"^(2)`. Initial angular speed of

2 Answers 4 Views

A particle of mass M is moving in a circular path of radius 2m. Its speed depends on the distance covered by the particle from the hegining according

2 Answers 4 Views

A radioactive element decays by `beta-`emission. A detector racords `n`-beta particles in `2` sec and in next `2` sec it records `0.65n`-beta particle

2 Answers 5 Views

An athelete completes one round of a circular track of radius `R` in 40 seconds. What will be the displacement at the end of ` 2 min. 20 second ?

2 Answers 9 Views

Particle running with constant speed v in circle of radius R then answer the following question. During running on circumference if particle made angl

2 Answers 5 Views

A particle starts moving from rest under a constant acceleration. It travels a distance x in the first 10 sec and distance y in the next 10 sec, then

2 Answers 4 Views

A body starts revolving from rest in a circular path of radius 2 m with tangential acceleration a `=2tm//s^(2)`. If its total acceleration at t=2 sec.

2 Answers 5 Views

A particle starts from rest on a straight path, Its acceleration is linearly varying with time, such that velocity of the particle at t=2 sec and t=4

2 Answers 5 Views

`d/(dx)sqrt((1-sin2x)/(1+sin2x))i se q u a lto,(0<x<pi/2),` `sec^2x` (b) `-sec^2(pi/4-x)` `sec^2(pi/4+x)` (d) `sec^2(pi/4-x)`

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`theta_(1)=(2pi)/(3)and theta_(2)=(2pi)/(3)"total time T"=2+1=3s therefore ltomega_(av)gt(theta_(1)+theta_(2))/(T)=((2pi)/(3)+(2pi)/(3))/(3)=((4pi)/(3))/(3)=(4pi)/(9)"rad/s"`

8 views Answered 2023-02-05 15:29