The third ionisation energy of `Al_((g))` is equal to :
The third ionisation energy of `Al_((g))` is equal to :
A. `IE_(1)" of "Al^(2+)(g)`
B. `IE_(2)" of "Al^(+)(g)`
C. `IE_(2)" of "Al^(2+)(g)`
D. `IE_(1)" of "Al^(+)(g)`
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Correct Answer - A::B
`Al_((g))overset(l.E_(1)" of "Al)rarrAl_((g))^(+)underset(l.E_(1)" of "Al_((g))^(2+))overset(l.E_(2)" of "Al_((g)))rarrAl_((g))^(2+)undersetunderset(l.E_(2)" of "Al_((g))^(+))(l.E_(1)" of "Al_((g))^(2+))overset(l.E_(3)" of "Al_((g)))rarrAl^(3+)`
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