If the binding energy of `2^(nd)` excited state of a hydrogen like sample os `24 eV` approximately, then the ionisation energy of the sample is approx

Question

If the binding energy of `2^(nd)` excited state of a hydrogen like sample os `24 eV` approximately, then the ionisation energy of the sample is approx

If the binding energy of `2^(nd)` excited state of a hydrogen like sample os `24 eV` approximately, then the ionisation energy of the sample is approximately
A. `54.4 eV`
B. `24 eV`
C. `122.4 eV`
D. `216 eV`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

An electron of a hydrogen like atom is in excited, state. If total energy of the electron is -4.6 eV, then evaluate (i) the kinetic energy and (ii) th

2 Answers 5 Views

The ionisation energy of hydrogen is 13.6 eV . The energy of the photon released when an electron jumps from the first excited state (n=2) to the grou

2 Answers 6 Views

When a hydrogen atom is excited from ground state to first excited state then

2 Answers 6 Views

An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the r

2 Answers 4 Views

A particular hydrogen like atom has its ground state Binding energy `= 122.4 eV`. It is in ground state. Then

2 Answers 9 Views

In a hydrogen atom, the electron is in `n^(th)` excited state. It may come down to second excited state by emitting ten different wavelengths. What is

2 Answers 5 Views

The ionisation energy of `H` atom is `21.79xx10^(-19) J`. The the value of binding energy of second excited state of `Li^(2+)` ion

2 Answers 6 Views

Calculate the energy required to excited one litre of hydrogen gas at `1` atm and `298 K` to the excited state of atomic hydrogen. The energy for the

2 Answers 9 Views

Hydrogen like atoms (atomic number `= Z`) in a sample are in excited state with principal quantum number n. The emission spectrum of the sample has `1

2 Answers 8 Views

A hydrogen like atom (atomic number = Z) is in higher excited state of quantum number n. This excited atom can make a transition to first excited stat

2 Answers 9 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`(13.6(Z)^(2))/((3)^(2))=24`
I.E. `=13.6(Z)^(2)=(24xx9)=216 ev`

4 views Answered 2023-02-05 15:29