The reduction potential of hydrogen electrode when placed in a buffer solution is found to be `-0.413V`. The pH of the buffer is

Question

The reduction potential of hydrogen electrode when placed in a buffer solution is found to be `-0.413V`. The pH of the buffer is

The reduction potential of hydrogen electrode when placed in a buffer solution is found to be `-0.413V`. The pH of the buffer is
A. 10
B. 4
C. 7
D. 12

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

For the cell prepared from electrode A and B, electrode A:`(Cr_2O_7^(2-))/(Cr^(3+)), E_("red")^(0)=+1.33V` and electrode B :`(Fe^(3+))/(Fe^(2+)), E_("

2 Answers 4 Views

the standard reduction potenital of a silver chloride electrode is 0.2 V and that of a silver electrode is 0.79 V. The maximum amount of AgCl that can

2 Answers 5 Views

What is the standard electrode potential for the electrode `MnO_(4)^(-)//MnO_(2)` in solution ? `("Given: "E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51" volt," E

2 Answers 5 Views

The `pH` of an acidic buffer solution & a basic buffer solution at `25^(@)C` is :

2 Answers 6 Views

Calculate the electrode potential at a copper electrode dipped in a 0.1 M solution of copper sulphate at `25^(@)C`. The standard electrode potential o

2 Answers 4 Views

What is the single electrode potential of a half-cell for zinc electrode dipping in 0.01 M `ZnSO_(4)` solution at `25^(@)C` ? The standard electrode p

2 Answers 8 Views

Calculate the electrode potential at `25^(@)C` of `Cr^(3+),Cr_(2)O_(7)^(2-)` electrode at `pOH=11` in solution of 0.01 M both in `Cr^(3+)` and `Cr_(2)

2 Answers 5 Views

The electrode potential becomes equal to standard electrode potential when reactants and products concentration ratio is:

2 Answers 5 Views

A hydrogen electrode placed in a buffer solution of `CH_(3)COONa` and `CH_(3)COOH` in the ratios of `x:y` and `y:x` has electrode potential values `E_

2 Answers 5 Views

A hydrogen electrode is immersed in a solution with pH = 0 (HCl). By how much will the potential (reduction) change if an equivalent amount of NaOH is

2 Answers 6 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`-0.413=0.059log((1)/([H^(+)]))` or `(0.414)/(0.059)=-logH^(+)=pH` or `pH=7`

5 views Answered 2023-02-05 15:29