What is the standard electrode potential for the electrode `MnO_(4)^(-)//MnO_(2)` in solution ? `("Given: "E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51" volt," E

Question

What is the standard electrode potential for the electrode `MnO_(4)^(-)//MnO_(2)` in solution ? `("Given: "E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51" volt," E

What is the standard electrode potential for the electrode `MnO_(4)^(-)//MnO_(2)` in solution ?
`("Given: "E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51" volt," E_(MnO_(2)//Mn^(2+))^(@)=1.23"volt")`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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`E_(Mn^(2+)//MnO_(4)^(-))^(0)=-1.51V` `E_(MnO_(2)//Mn^(+2))^(0)=+1.23V` `E_(MnO_(4)^(-)//MnO_(2)=?` (All in acidic medium)

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 1.7 volt
`{:(MnO_(4)^(-)+8H^(+)+5e^(-) rarr Mn^(2+)+4H_(2)O," "E^(@)=1.51" volt"),(MnO_(2)+4H^(+)+2e^(-) rarr Mn^(2+)+2H_(2)O," "E^(@)=1.23" volt"),("Subtracting"),(bar(MnO_(4)^(-)+4H^(+)+3e^(-) rarr MnO_(2)+2H_(2)O," "E^(@)=?" ")):}`
`E^(@)=(5xx1.51-2xx1.23)/(3)=(7.55-2.46)/(3)=5.09/3=1.70` volt

5 views Answered 2023-02-05 15:29