Statement-1: if an aqueous solution of `NaCl` is electroysed, the product obtained at the cathode is `H_(2)` gas and not Na.
Statement-2: Gases are liberated faster than the metals during the electrlysis of electrolyte.

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1 Answers

`H_(H^(+)//H_(2)^(@)gtE_(Na^(+)//Na)^(@)` so, that `H_(2)` gas will have more tendency to get deposit.

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