Gas (A) and gas(B) both turn `K_(2)r_(2)O_(7)//H^(+)` green. Gas (A) alos turbs lead acetate paper black. When gas (A) is passed into gas (B) in ann aqueous solution, yellowish white turbidiyt appears. Identify gas (A) and (B) and explain the reactions.

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The information suggest that the gas (A) is `H_(2)S` while the gas (B) is `SO_(2)`. Both turn acidified `K_(2)Cr_(2)O_(7)` paper green.
`K_(2)Cr_(2)O_(7)+4H_(2)SO_(4)+underset("(Gas A)")(3H_(2)S) to K_(2)SO_(4) + underset("(green)")(Cr_(2)(SO_(4))_(3))+7H_(2)O+3(S)`
`K_(2)Cr_(2)O_(7)+H_(2)SO_(4)+underset("(Gas B)")(3SO_(2)) to K_(2)SO_(4) + underset("(green)")(Cr_(2)(SO_(4))_(3))+H_(2)O`
`underset("(Gas A)")(H_(2)S)+(CH_(3)COO)_(2)Pb to underset("(Black ppt.)")(PbS)+2CH_(3)COOH`
`underset("(Gas A)")(2H_(2)S)+underset("(Gas B)")(SO_(2)) to 2H_(2)O+underset("(Yellowish turbidity )")(3S)`

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