When heating white lead then find out released gas `(A)` and `(B)`
`underset("white lead")(2PbCO_(3)).Pb(OH)_(2) overset(Delta)Pb_(3)O_(4) + (A) +(B) +H_(2)O`
A. `CO, O_(2)`
B. `CO_(2), O_(2)`
C. `CO_(2), CH_(4)`
D. `CO, CO_(2)`

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Correct Answer - D
`2PbCO_(3).Pb(OH)_(2)overset(Delta)toPb_(3)O_(4)+CO+CO_(2)+H_(2)O`

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