Using the `triangleG^(0)` for the reaction `C+O_(2)toCO_(2)triangleG^(0)=-395kJ//"mole"` `2A(l)+3//2O_(2)toAl_(2)O_(3)(s)triangleG^(0)=-1269kJ//"mole"

Question

Using the `triangleG^(0)` for the reaction `C+O_(2)toCO_(2)triangleG^(0)=-395kJ//"mole"` `2A(l)+3//2O_(2)toAl_(2)O_(3)(s)triangleG^(0)=-1269kJ//"mole"

Using the `triangleG^(0)` for the reaction
`C+O_(2)toCO_(2)triangleG^(0)=-395kJ//"mole"`
`2A(l)+3//2O_(2)toAl_(2)O_(3)(s)triangleG^(0)=-1269kJ//"mole"`
`Al_(2)O_(3)("melt")+3Cto4Al(l)+3CO_(2)(g)`
Calculate the EMF for thhe cell reaction
`2Al_(2)O_(3)("melt")+3Cto4Al(l)+3CO_(2)(g)`
the number of electrons involved in the reaction is 12.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - `-1.14"volt"`
`2Al_(2)O_(3)("melt")to2Al_(2)O_(3)(s)" "triangleG_(1)^(@)=-2xx16`
`2Al_(3)O_(3)(s)to4A(l)+3O_(2)(g)" "triangleG_(2)^(@)=2xx1269`
`3C+3O_(2)to3CO_(2)" "triangleG_(3)^(@)=-3xx395`
`2Al_(2)O_(3)("melt")+3Cto4Al(l)+3CO_(2)(g)`,
`triangleG^(@)=triangleG_(1)^(@)+triangleG_(2)^(@)+triangleG_(3)^(@)=-32+2xx1269-3xx395=1321kJ`
`triangleG^(@)=-nFE^(@)implies1321xx10^(3)=-12xxE^(@)xx96500`
`E^(@)=-1.14` volt