Calculate the free energy change at 298 K for the reaction, `Br_(2)(l)+ Cl_(2)(g) rarr 2BrCl(g)`. For the reaction `DeltaH^(@)=29.3` KJ & the entropie

Calculate the free energy change at 298 K for the reaction,
`Br_(2)(l)+ Cl_(2)(g) rarr 2BrCl(g)`. For the reaction `DeltaH^(@)=29.3` KJ & the entropies of `Br_(2)(l),Cl_(2)(g)` & `BrCl(g)` at the 298 K are 152.3,223.0,239.7 J `"mol^(-1)K^(-1)` respectively.
A. `-1721.8 J`
B. `-60321.8 J`
C. `+60321.8 J`
D. `+1721.8J`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - A
`DeltaG-29.3 xx10^(3)-(2xx239.7 - 152.3 -223)xx298 =-1721.8 "Joule".`

4 views Answered 2023-02-05 15:29

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