Calculate `DeltaS_(r)^(@)` at 298 K of , (i) `Na(s) +(1)/(2)CL_(2)(g) to NaCl(s)`, (ii) `(1)/(2) N_(2)(s) + 2H _(2)(g) +(1)/(2) Cl_(2)(g) to NH_(4) Cl

Question

Calculate `DeltaS_(r)^(@)` at 298 K of , (i) `Na(s) +(1)/(2)CL_(2)(g) to NaCl(s)`, (ii) `(1)/(2) N_(2)(s) + 2H _(2)(g) +(1)/(2) Cl_(2)(g) to NH_(4) Cl

Calculate `DeltaS_(r)^(@)` at 298 K of ,
(i) `Na(s) +(1)/(2)CL_(2)(g) to NaCl(s)`,
(ii) `(1)/(2) N_(2)(s) + 2H _(2)(g) +(1)/(2) Cl_(2)(g) to NH_(4) Cl(s)`
(iii) C(graphite) to C( diamond).
The values of `S^(@)` of ` Na, Cl_(2), NaCl, NH_(4) Cl, N_(2), H_(2)`,"diamond& graphite are" 51, 223,72,95 ,192,
131, 2.43 & `5.69 JK^(-1) mol^(-1)` respectively .

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - (i) - 90.5 (ii) - 374.5 (iii) `- 3.26 ("all in J mol"^(-1) K^(-1))`.
`(DeltaS)_(R)= sum(S^(@))_("Product")-sum(S^(@))_("Reactants")`
(i) `" "DeltaS = 72 - [51+(223)/(2)]`
`= - 90.5 J K^(-1) "Mole"^(-1)` (ii) `" " (DeltaS^(@))_(R) = - 374.5 J//K-"Mole"`
(iii) `" "(DeltaS^(@))_(R) = - 3.26 J//K-"Mole"`

9 views Answered 2023-02-05 15:29