If `DeltaH_(f(C_(2)H_(6)))^(0)(g) = -85 KJH mol^(-1) , DeltaH_(f(C_(3)H_(8)))^(0) (g) = -104 KJ mol^(-1), DeltaH^(0)` for `C (s) rarr C(g)` is `718 KJ

Question

If `DeltaH_(f(C_(2)H_(6)))^(0)(g) = -85 KJH mol^(-1) , DeltaH_(f(C_(3)H_(8)))^(0) (g) = -104 KJ mol^(-1), DeltaH^(0)` for `C (s) rarr C(g)` is `718 KJ

If `DeltaH_(f(C_(2)H_(6)))^(0)(g) = -85 KJH mol^(-1) , DeltaH_(f(C_(3)H_(8)))^(0) (g) = -104 KJ mol^(-1), DeltaH^(0)` for `C (s) rarr C(g)` is `718 KJ mol^(-1)` and heat of formation of H-atom is `218 KJmol^(-1)` then :
A. `DeltaH_(C-C) = 345` KJ
B. `DeltaH_(C-H) = 414` KJ
C. `DeltaH_(H-H)=436 KJ`
D. `DeltaH_(H-H) = 436` KJ

Monjur Alahi

9 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - A::B::C
`2C + 3H_(2) rarr C_(2)H_(6)`
Also, `DeltaH_(f(C_(2)H_(6)))^(0) (g) = 2xx 718 + 3xx436 - a - 6b" " (DeltaH_(C-C) = a, DeltaH_(C-H) = b)`
`a+ 6b = 2829" ""…."(i)`
`3C + 4H_(2) rarrC_(2)H_(8)`
`DeltaH_(f(C_(3)H_(8)))^(0) (g) = 3xx 718 + 4 xx 436 - 2a - 8b`
`2a + 8b = 4002" ""....."(ii)`
`a = 345 "&" b=414 KJ.`