Cadmium amalgam is prepared by electrolysis of a solution of `CdCl_(2)` using a mercury cathode. Find how long a current of 5 ampere should be passed

Question

Cadmium amalgam is prepared by electrolysis of a solution of `CdCl_(2)` using a mercury cathode. Find how long a current of 5 ampere should be passed

Cadmium amalgam is prepared by electrolysis of a solution of `CdCl_(2)` using a mercury cathode. Find how long a current of 5 ampere should be passed in order to prepare 12% Cd-Hg amalgam on a cathode of 2 g mercury. At mass of Cd=112.40.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

A current of 0.1A was passed for 4hr through a solution of cuprocyanide and 0.3745 g of copper was deposited on the cathode. Calculate the current eff

2 Answers 12 Views

Electrolysis of a solution of `HSO_4^(-)` ions produces `S_2O_2^(--)`, Assuming 75% current efficiency , what current should be employed to achieve a

2 Answers 7 Views

A 100 watt, 110 volt incandescent lamp is connected in series with an electrolytic cell containing cadmium sulphate solution. What mass of cadmium wil

2 Answers 4 Views

How long has a current of 3 ampere to be applied through a solution of silver nitrate to coat a metal surface of `80 cm^(2)` with 0.005 mm thick layer

2 Answers 6 Views

A current of 3.7 ampere is passed for 6 hours between platinum electrodes in 0.5 litre of a 2 M solution of `Ni(NO_(3))_(2)`. What will be the molarit

2 Answers 5 Views

How long a current of 3 ampere has to be passed through a soulution of silver nitrate to coat a metal. Surface of `80cm^(2)` with a 0.005 mm thick lay

2 Answers 5 Views

During the electrolysis of 0.1 M `CuSO_(4)` solution using coppepr electrodes, a depletion of `[Cu^(2+)]` occurs near the cathode with a corresponding

2 Answers 5 Views

Zn amalgam is prepared by electrolysis of aqueous `ZnCl_(2)` using Hg cathode (9gm) How much current is to be passed through `ZnCl_(2)` solution for 1

2 Answers 9 Views

A current of 1.0 A was passed for 2 hr through a solution of cuprocyanide and 0.3745 g of copper was deposited on the cathode. Calculate the current e

2 Answers 5 Views

Complete the following reaction: `2C_(2)H_(5)MgCl+CdCl_(2)to(A)+2MgCl_(2),(A)+2CH_(3)-overset(O)overset(||)C-Cl to(B)+CdCl_(2)`

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

2g Hg require Cd to prepare 12% amalgam
`=12/88xx2=0.273 g`
`underset(("1 mole"),(112.40 g))(Cd^(2+))+underset(2xx96500 C)(2e^(-))rarr Cd`
Charge required to deposite 0.273 g of Cd
`=(2xx96500)/112.40xx0.273` coulomb
Charge = ampere `xx` second
Second `=(2xx96500xx0.273)/(112.40xx5)=93.75`

4 views Answered 2023-02-05 15:29