The speed of a certain proton is `0.45 Mms^(-1)`. If the uncertainty in its momentum is to `b` reduced to `0.0100` percent, what incertainty in its location must be tolerated?
A. `0.60 nm`
B. `0.72 nm`
C. `0.80 nm`
D. `0.70 nm`

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1 Answers

Correct Answer - D
`Deltap ~~0.010 perce of p_(0)=p_(0)xx(1.00xx10^(-4))=m_(p)vxx(1.00xx10^(-4))(p_(0)=m_(p)v)`
`Deltaq~~(h)/(2Deltap)~~(1.055xx10^(-34) Js)/((2)xx(1.673xx10^(-27) kg)xx(4.5xx10^(5) ms^(-1))xx(1.00xx10^(-4)))~~7.01xx10^(-10) m, "or" 0.70 nm`

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